JEE Main Normalization Procedure 2025: NTA (National Testing Agency) conductsJEE Main 2025. With the introduction of the newly formed exam conducting body, major changes have been done at the procedure of JEE Mains. Every year, around 14 lakh candidates appear for the exam from various State and Central Boards across the country. The selection of the candidate is based on JEE Main marks and counselling. NTA has released the result online on the official site. Candidates can click on the link below to check.

Check Eligibility For NTA JEE Main Exam

What Is JEE Main Normalization Procedure 2025?

The often conflicted issue is the difficulty level of the exam which varies in each session which results in some of the candidates ending up with a difficult set of papers. Naturally, the candidate with a more difficult set of exams scores less in the exam in comparison to candidates getting an easier set of the question paper. The JEE Main 2025 will take place in February, March, April, and May. The exam of all four sessions has been over.

How To Calculate Percentile In JEE Main 2025?

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After the declaration of the JEE Main 2025 February exam, candidates can check their expected rank from the formula provided below. The candidate will have to multiply their percentile to 100 which will be divided by 100. The provided score will be multiplied again with the total number of candidates who appeared for the exam. The candidate must note that the below-provided formula will only provide the estimated rank of the respective session 2025. The rank might vary after the April exam. The declaration of the final rank will be released by the National Testing Agency (NTA) after JEE Main Feb/March/April/May 2025 exam.

Details Of JEE Main Normalization Procedure 2025

The National Testing Agency (NTA) will release the JEE Main result for each session in the form of a normalized score. This will help in resolving issues of discrepancy in the difficulty level of each session. To understand how the normalization procedure takes place, read further.

For Example, there two students, candidate A, and candidate B.

  1. Candidate A has taken JEE Main 2025 in shift 1 one and scored a raw mark of 340 out of 360. He is the highest scorer among all the shift 1 candidates where 56789 candidates appeared.
  2. Candidate B has taken JEE Main 2025 in shift 2 and scored 310 out of 260. She is the highest scorer among all the shift 2 candidates where 54689 candidates appeared.

Now, considering only the raw scores of these two candidates to prepare the merit list, candidate A will be the topper with a higher rank. However, if shift 2 is more difficult than shift 1 then this will be unfair for candidate B who took a more difficult paper and got fewer scores.

This is where JEE Main Normalization Procedure comes in. Let us see how the ranks change with the normalization procedure.

Shift 1: Total candidates who appeared = 56789

Candidates who scored equal to or less than the topper of shift 1 = 56789

Percentile Obtained = 100 (56789/56789)

Percentile Obtained = 100

Shift 2: Total candidates who appeared = 54689

Candidates who scored equal to or less than the topper of shift 2 = 54689

Percentile Obtained = 100 (54689/54689)

Percentile Obtained = 100

This shows us that although both candidates had a different score, based on their difference of difficulty level, both got the same percentile which is 100.

Now let us take 4 more candidates C, D, E, and F.

  1. Candidate C & D have a raw total score of 330 and secured the 2nd position in shift 1.
  2. Candidate E has a raw total score of 304 and secured the 3rd position in shift 1.
  3. And candidate F has a raw total score of 304 and secured the 2nd position in shift 2.

If the raw score of candidates is taken into consideration, the merit list will be something like this:

Candidate A 3401st Position
Candidate B 3103rd Position
Candidate C 3302nd Position
Candidate D 3302nd Position
Candidate E 3044th Position
Candidate F 3044th Position

If we consider these ranks of the candidate, then it will be unfair for Candidate F to be in the 4th position as shift 2 was difficult than shift 1 and also his rank is equal to candidate E. This happens because of the difference in the difficulty level of the various shifts held.

If we change these scores to percentile scores, the following will be the result:

Percentile of candidate A = 100 (56789/56789) = 100

Percentile of candidate B = 100 (54689/54689) = 100

Candidate C percentile= 100 (56788/56789) = 99.99823909

Percentile of candidate D = 100 (56788/56789) = 99.99823909

Percentile of candidate E = 100 (56786/56789) = 99.99471728

Candidate F percentile= 100 (54688/54689) = 99.99817147

Based on this percentile score, the ranks awarded will be something like this:

Candidate A 3401st Position
Candidate B 3101st Position
Candidate C 3302nd Position
Candidate D 3302nd Position
Candidate F 3043rd Position
Candidate E 3044th Position

This is how the normalization procedure will take place and candidates will be awarded a rank after their score is normalized and changed into a percentile score.

National Testing Agency is using the policy of ‘JEE Main Normalization Procedure based on percentile Score’ to overcome such problem of the unequal gain of marks. The Normalization Procedure was utilized earlier also for equalization of class 12th marks to bring all the boards on the same level. Now the normalization Procedure will be used for the JEE Main score which will be based on Percentile Score to ensure that the level of exam is equal for every candidate appearing for JEE Main 2025. Normalization is done to make sure there is no uneven difficulty level in the exam.

NTA’s New Percentile Score Based On JEE Main Normalization

Percentile Score: Percentile Score is the marks obtained by the candidate and is transformed into a scale ranging from 0 to 100. The purpose is to compare the scores of the candidates in multiple sessions. Percentile Score will be the normalized score of the examination.

JEE Main Normalization Procedure 2025 as per NTA

NTA Normalized Score

How Will The Procedure Of JEE Main 2025 Normalization Work?

  • Candidates should know that the raw scores of candidate secured in JEE Main 2025 based on the marking scheme will be calculated.
  • Each correct answer will add up the 4 marks and a negative marking of 1 marks will be for each incorrect answer.
  • The calculation of the overall score of JEE Main 2025 is by comparing the raw score of the candidate in comparison to all the candidates.
  • The percentile secured by the candidate means the percentage of the candidates who have secured less than you in the JEE Main exam or the percentage of candidates from whom you have secured above in the exam.

To understand this procedure go through the example explained:
In the case where  Arun’s percentile is 95 in an exam taken by 1000 students, it means that 95% of 1000 students i.e. 950 students have scored below Arun.
How will the Result of JEE Main 2025 be prepared?

  • The preparation of the result of JEE Main 2025 is based on a raw score and the percentile score of Total and all the three subjects (Physics, Chemistry, Mathematics).

Total Percentile (T1P)

Let T1, M1, P1, C1 be the raw scores in Total, Mathematics, Physics, Chemistry of a candidate and T1P, M1P, P1P, C1 be the Percentile Scores of Total, Mathematics, Physics, Chemistry of that candidate.

Compilation & Display of Result For Multi-Session Papers of JEE Main 2025

Since the examination of JEE Main 2025 will be held twice this year by the National Testing Agency, it is important for the aspirants that they are aware of the procedure and the calculation of the Result by the examination authorities. Given the difficulty level of this exam, the scores of the candidates from both the attempts will be taken for the final result and the preparation of the Merit List. Explaining this procedure further, we are providing a detailed explanation of the Result calculation and the preparation of the Merit List of JEE Main 2025 in the points below.

Compilation of Result for First attempt:

Since the first attempt will be conducted in multi-session, NTA scores will be calculated corresponding to the raw marks obtained by a candidate in each session as per the above procedure. The calculated NTA scores for all the sessions will be merged for the declaration of result. The result shall comprise the four NTA scores for each of the three subjects (Mathematics, Physics, and Chemistry) and the total for the first attempt.

Compilation of Result for Second attempt:

Similarly, the second attempt will be conducted in multi-session, NTA scores will be calculated corresponding to the raw marks obtained by a candidate in each session as per the above procedure. The calculated NTA scores for all the sessions will be merged for the declaration of result. The result shall comprise the four NTA scores for each of the three subjects (Mathematics, Physics, and Chemistry) and the total for the second attempt.

Compilation of Result and Preparation of Merit List / Ranking:

The four NTA scores for each of the candidates for the first attempt as well as for the second attempt will be merged for the compilation of results and preparation of the overall Merit List / Ranking. Those who appear in both the attempts; their best of the two NTA scores will be taken into consideration for the preparation of Merit List /Ranking. The example is given below.

NTA Combined Normalized ScoreExpected JEE Main 2025 Marks Vs Percentile

PercentileScore
0.843517743614459 – 9.695406622010480 – 10
13.4958497103427 – 33.229128336052411 – 20
37.6945295632834 – 56.569310977019521 – 30
58.1514901857346 – 71.302052295712131 – 40
73.2878087751462 – 80.982153808746941 – 50
82.0160627661434 – 86.907944654120851 – 60
87.5122250914779 – 90.702200570739461 – 70
91.0721283110867 – 93.152971850539671 – 80
93.4712312797351 – 94.749479246380881 – 90
94.9985943180054 – 96.064850243307891 – 100
96.2045500677875 – 96.9782721725982101 – 110
97.1429377776765 – 97.6856721385145111 – 120
97.8112608696124 – 98.2541321080562121 – 130
98.3174149345299 – 98.6669358629096131 – 140
98.7323896268267 – 98.9902969950969141 – 150
99.0286140409721 – 99.2397377073381151 – 160
99.272084675244 – 99.4312143898418161 – 170
99.4569399985455 – 99.573193698637171 – 180
99.5973996511304 – 99.6885790237511181 – 190
99.7108311325455 – 99.7824720681761191 – 200
99.7950635053476 – 99.845212160289201 – 210
99.8516164257469 – 99.8937326121479211 – 220
99.9011137994553 – 99.9289017987302221 – 230
99.9349804235716 – 99.9563641573886231 – 240
99.9601632979145 – 99.9750342194015241 – 250
99.9772051568448 – 99.9888196721667250 – 262
99.9909906096101 – 99.9940299220308263 – 270
99.9946812032638 – 99.997394875068271 – 280
99.99989145300

JEE Main 2020 Marks Vs Percentile

Candidates can refer below to check the approximate percentile based on the jee main scores. 

JEE Main MarksJEE Main Percentile
360 to 310100 – 99.9872475
309 to 29999.9855721 – 99.9740296
298 to 28899.9758912 – 99.9625802
287 to 27899.9614632 – 99.9442427
277 to 26899.9409848 – 99.9192962
267 to 25899.9183654 – 99.8908126
257 to 24899.8864376 – 99.8484594
247 to 23899.8451084 – 99.7995904
237 to 22899.7967979 – 99.7329423
227 to 21899.7300567 – 99.6547519
217 to 20899.6488876 – 99.5527320
207 to 19899.5491948 – 99.4360979
197 to 18899.4200875 – 99.2895839
187 to 17899.2647305 – 99.0778181
177 to 16899.0632970 – 98.8568370
167 to 15898.8250954 – 98.5571069
157 to 14898.5310434 – 98.2004095
147 to 13898.1493996 – 97.7568649
137 to 12897.6947779 – 97.1764870
127 to 11897.1384157 – 96.4199013
117 to 10896.3551149 – 95.4974401
107 to 9895.4267895 – 94.4012845
97 to 8894.1947314 – 92.7470911
87 to 7892.6189146 – 90.6422786
77 to 6890.4290235 – 87.3418039
67 to 5887.3418039 – 82.6801638
57 to 4881.9257190 – 75.3902075
47 to 3874.1345061 – 64.1130038
37 to 2862.8883924 – 49.2876291
27 to 1849.0122870 – 33.0881504
17 to 131.3257004 – 9.0775388

Expected JEE Main Percentile Vs Rank 2025

Candidates must note that the rank is obtained as per the percentile scores. Hence, the applicants can check the expected JEE Main rank 2025 as per the percentile scores.

NTA JEE Main Scores 2025Expected ranks
1001
998750
9817,500
9726,200
9635,000
9535,000
9452,400
9361,200
9270,000
9178,700
9087,450
851,31,100
801,74,900
702,62,350
603,49,800
504,37,240
405,24,700
306,12,150
206,99,600
107,87,000
058,30,750
08,74,470

JEE Main Answer Key 2025

After the completion of the JEE Mains exam 2025, NTA will release the official JEE Main Answer Key for the same. The Answer Key will contain correct responses to the questions asked in the exam. So, the candidates can check their estimated scores based on the NTA JEE Main Answer Key. Also, NTA provides the opportunity to challenge the official answer key. Candidates who feel that the answers given in the answer key are wrong can raise their objections by writing an application and submitting the required fee. All those who are going to appear for JEE Main 2025 can download the answer key.

JEE Main Previous Years Cutoff (2020, 2019, 2018, 2017, 2016, 2015, 2014)

Candidates can check the JEE Main Cutoff to prepare efficiently.

JEE Main 2020 Cutoff

CategoryJEE Main Paper 1 Cut Off 2020
PwD0.0618524
Common Rank List (CRL)90.3765335
General-EWS70.2435518
Other Backward Classes (OBC-NCL)72.8887969
Scheduled Tribe (ST)39.0696101
Scheduled Caste (SC)50.1760245

 

JEE Main 2019 Cutoff

CategoryJEE Main Paper 1 Cut Off 2019 (Percentile)
PwD0.11371730
Common Rank List (CRL)89.7548849
General-EWS78.2174869
Other Backward Classes (OBC-NCL)74.3166557
Scheduled Tribe (ST)44.3345172
Scheduled Caste (SC)54.0128155

JEE Main Cutoff (2018, 2017, 2016, 2015, 2014)

Category20182017201620152014
UR748110010549
OBC4549704774
SC2932525070
ST2427484470

 

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