JEE Main 2019 Percentile Vs Rank: The JEE Main 2019 results will be declared on 31st April and 15th May for Paper I and II of JEE Main 2019 for the second attempt of Joint Entrance Examination being conducted for the second time by NTA. The results for all candidates were published in the form of percentile score and the scorecard contained only the percentile score of Physics, Chemistry and Mathematics along with the total percentile score. The raw marks of candidates were not displayed on the scorecard or anywhere else.

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The JEE Main 2019 second session will be conducted from 7th to 20th April 2019 and the results will be declared on 30th April and 15th May in the form of a percentile score. Please make sure to keep your JEE Main 2019 Admit card safely as it will be used even after the result has been declared. In order to remove any kind of discrepancy in the calculation of marks for the different shifts of a single day, the raw marks of each candidate were converted to percentile scores

JEE Main 2019 ResultsJEE Main 2019 Official Answer Sheet

Now the question that almost all students are asking is related to the JEE Main 2019 percentile vs rank – how can one check the rank using the percentile score? The answers have been provided below.

What is JEE Main 2019 Percentile Vs Rank?

Before we move ahead, let’s check what these two terms Percentile and rank mean regarding JEE Main 2019.

Percentile scores are scores based on the relative performance of all those who appear for the examination. Basically, the marks obtained are transformed into a scale ranging from 100 to 0 for each session of candidates.

Check the formula to calculate the JEE Main 2019 Percentile:

How to Calculate Percentile score

Percentile Score of a Candidate = 100 x (No. of candidates who secured a raw score (or actual score) EQUAL TO OR LESS than the candidate) / (Total number of candidates who appeared in that session).

Ranks are the performance scores of the candidates that are allotted based on the candidate’s score in the examination. So, the higher the JEE Main 2019 rank, the better institute, and preference will a candidate get.

JEE Main 2019 Percentile Vs Rank: How to calculate an expected Rank from Percentile?

Well, you can check the expected rank using a formula given below. Here 874469 is the total number of candidates (in Jan session) and percentile is the total percentile score of the candidate.

So for example, if a candidate has obtained 70 percentile, he/she can simply put 70 in the below-given formula which will result in an expected rank of 2,62,342.

JEE Main 2019 Percentile Vs Rank

JEE Main 2019 Percentile Vs Rank

Based on this formula, we have written down the expected JEE Main rank 2019 based on a few jee main 2019 percentile scores. Please note that this is not the final rank and a safe assumption.

You too can use this method to know what your expected rank will be in the JEE Main 2019 January session.

Percentile Scores (NTA Score)Expected Rank
1001
998746
9817,490
9726,235
9634,980
9543,724
9452,469
9361,214
9269,959
9178,703
9087,448
851,31,171
801,74,895
702,62,342
603,49,789
504,37,236
405,24,682
306,12,129
206,99,576
107,87,023
58,30,747
08,74,469

JEE Main Percentile Vs Rank 2019: Normalization Procedure

The National Testing Agency (NTA) will be releasing the JEE Main 2019 result for session 2 (April) in the form of a normalized score. This will help in resolving issues of discrepancy in the difficulty level of each session. To understand how the normalization procedure takes place, read further.

For Example, there two students, candidate A, and candidate B.

  1. Candidate A has taken JEE Main 2019 in shift 1 one and scored a raw mark of 340 out of 360. He is the highest scorer among all the shift 1 candidates where 56789 candidates appeared.
  2. Candidate B has taken JEE Main 2019 in shift 2 and scored 310 out of 260. She is the highest scorer among all the shift 2 candidates where 54689 candidates appeared.

Now, considering only the raw scores of these two candidates to prepare the merit list, The candidate A will be the topper with a higher rank. However, if shift 2 was more difficult than shift 1 then this will be unfair for candidate B who had to take a more difficult paper and scored less.

This is where NTA Normalization Procedure comes in. Let us see how the ranks change with the normalization procedure.

Shift 1: Total candidates who appeared = 56789

Candidates who scored equal to or less than the topper of shift 1 = 56789

Percentile Obtained = 100 (56789/56789)

Percentile Obtained = 100

Shift 2: Total candidates who appeared = 54689

Candidates who scored equal to or less than the topper of shift 2 = 54689

Percentile Obtained = 100 (54689/54689)

Percentile Obtained = 100

This shows us that although both candidates had a different score, based on their difference of difficulty level, both got the same percentile which is 100.

Now let us take 4 more candidates C, D, E, and F.

  1. Candidate C & D have a raw total score of 330 and secured the 2nd position in shift 1.
  2. Candidate E has a raw total score of 304 and secured the 3rd position in shift 1.
  3. Candidate F has a raw total score of 304 and secured the 2nd position in shift 2.

If the raw score of candidates will be considered, the merit list will be something like this:

Candidate A 3401st Position
Candidate B 3103rd Position
Candidate C 3302nd Position
Candidate D 3302nd Position
Candidate E 3044th Position
Candidate F 3044th Position

If we consider these ranks of the candidate, then it will be unfair for Candidate F to be on the 4th position as shift 2 was difficult than shift 1 and also his rank is equal to candidate E. This happens because of the difference in the difficulty level of the various shifts held.

If we change these scores to percentile scores, the following will be the result:

Percentile of candidate A = 100 (56789/56789) = 100

Percentile of candidate B = 100 (54689/54689) = 100

Percentile of candidate C = 100 (56788/56789) = 99.99823909

Percentile of candidate D = 100 (56788/56789) = 99.99823909

Percentile of candidate E = 100 (56786/56789) = 99.99471728

Percentile of candidate F = 100 (54688/54689) = 99.99817147

Based on this percentile score, the ranks awarded will be something like this:

Candidate A 3401st Position
Candidate B 3101st Position
Candidate C 3302nd Position
Candidate D 3302nd Position
Candidate F 3043rd Position
Candidate E 3044th Position

This is how the normalization procedure will take place and candidates will be awarded a rank after their score is normalized and changed into a percentile score.

Things to Note

  • Those who have a higher percentile score will be awarded a higher rank and thus, will be given the highest priority.
  • In case there is a tie between two candidates, the tie-breaking policy will be used.
  • If a candidate takes both January and April exam sessions, the best out of both the total percentiles will be taken into consideration. The subject-wise score will not be taken into consideration.
  • Also, if the aspirant appears for JEE Main 2019 either in January or in April, both Total and Subject-wise Percentile Scores will be taken into consideration.
  • The percentile score obtained indicates the number of candidates who scored less than or equal to your raw score.
  • The ranks allotted will be based on your percentile score.

If you have any query, do ask us in the comments section below!

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Jennefer Reggie is a young girl from New Delhi. She has done graduation in English Honours from DU. Her interests vary from watching stand-up comedy and trekking to sitting with a coffee while reading a book. She says she laughs like a seal but she's mostly a normal girl with a poker face most of the time. Jennefer is an enthusiastic writer and currently working as an executive content writer.

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